x+4/x-2*x^2+4x-12/3x+12

Solution for x+4/x-2*x^2+4x-12/3x+12 equation:

D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

x-(2*x^2)+4*x-((12/3)*x)+4/x+12 = 0

x-2*x^2+4*x-4*x+4/x+12 = 0

1*x^1-2*x^2+4*x^-1+12*x^0 = 0

(1*x^2-2*x^3+12*x^1+4*x^0)/(x^1) = 0 // * x^2

x^1*(1*x^2-2*x^3+12*x^1+4*x^0) = 0

x^1

x^2-2*x^3+12*x+4 = 0

{ 1, -1, 2, -2, 4, -4 }

1

x = 1

x^2-2*x^3+12*x+4 = 15

1

-1

x = -1

x^2-2*x^3+12*x+4 = -5

-1

2

x = 2

x^2-2*x^3+12*x+4 = 16

2

-2

x = -2

x^2-2*x^3+12*x+4 = 0

-2

x+2

5*x-2*x^2+2

x^2-2*x^3+12*x+4

x+2

2*x^3+4*x^2

5*x^2+12*x+4

-5*x^2-10*x

2*x+4

-2*x-4

0

5*x-2*x^2+2 = 0

DELTA = 5^2-(-2*2*4)

DELTA = 41

DELTA > 0

x = (41^(1/2)-5)/(-2*2) or x = (-41^(1/2)-5)/(-2*2)

x = (41^(1/2)-5)/(-4) or x = (41^(1/2)+5)/4

x in { (41^(1/2)-5)/(-4), (41^(1/2)+5)/4, -2} 

x in { (41^(1/2)-5)/(-4), (41^(1/2)+5)/4, -2 }